2x^2-0.25x-1.5=0

Solution for 2x^2-0.25x-1.5=0 equation:

2x^2-0.25x-1.5=0

a = 2; b = -0.25; c = -1.5;
Δ = b2-4ac
Δ = -0.252-4·2·(-1.5)
Δ = 12.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{12.0625}}{2*2}=\frac{0.25-\sqrt{12.0625}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{12.0625}}{2*2}=\frac{0.25+\sqrt{12.0625}}{4}
$